diketahui f(x) = x2 - 7 ; g(x) = akar x+7 . tentukanlah (fog) (x)
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[tex]f(x) = {x}^{2} - 7 [/tex]
[tex]g(x) = \sqrt{(x + 7)} [/tex]
Maka,
[tex](fog)(x) = f(g(x))[/tex]
[tex](fog)(x) = f({ \sqrt{(x + 7)}})[/tex]
[tex](fog)(x) = ( { \sqrt{(x + 7)} )}^{2} - 7[/tex]
[tex](fog)(x) =(x + 7) - 7[/tex]
[tex](fog)(x) =x + 7 - 7[/tex]
[tex](fog)(x) = x + 0[/tex]
[tex](fog)(x) = x[/tex]
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